My math professor presented this problem .. nobody was able to complete it for the test the day prior, so this is a review.

AB ∩ CD = {E}
AB = 15
CD = 20

The video cuts off before finishing the problem .. but chances are if you can understand thus far, you can solve the remaining algebra:

Since you have 4y=x, substitute it into the equation to become this:
60 -4(4y) = 20 -y
60 -16y = 20 – y
40 = 15y
40/15 = y
8/3 = y

Then, substitute the y into the 4y=x to get x:
4(8/3) = x
32/3 = x

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